0=x^2/10+9x/10+11/5

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Solution for 0=x^2/10+9x/10+11/5 equation: 


x in (-oo:+oo)

0 = (x^2)/10+(9*x)/10+11/5 // - (x^2)/10+(9*x)/10+11/5

0-((x^2)/10)-((9*x)/10)-(11/5) = 0

(-9/10)*x-((x^2)/10)-11/5 = 0

-1/10*x^2-9/10*x-11/5 = 0

DELTA = (-9/10)^2-(-11/5*(-1/10)*4)

DELTA = -7/100

DELTA < 0

x belongs to the empty set

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